Given the following reactions N₂ (g)+ O₂ (g)→ 2NO (g)ΔH = +180.7 kJ 2NO (g)+ O₂(g)→ 2N (g)ΔH = -113.1 kJ The enthalpy of reaction for 4NO (g)→ 2NO₂ (g)+ N₂ (g) Is ________ kJ. A)67.6 B)45.5 C)-293.8 D)-45.5 E)293.8

Question

Quizplus · Accepted Answer

To find the enthalpy of the desired reaction, we need to combine the given reactions. First, flip the second reaction and multiply it by 2 to cancel out the NO terms.

2N2O (g) + O2 (g) → 2NO (g) + 2NO2 (g) ΔH = -226.2 kJ

Next, multiply the first reaction by 2 and add it to the above equation to get the desired reaction.

2N2O (g) + O2 (g) + 2SO2 (g) → 4NO (g) + 2SO3 (g) ΔH = -45.5 kJ

Therefore, the enthalpy of the desired reaction is -45.5 kJ.

Given the Following Reactions N2 (G)+ O2 (G)→ 2NO (G)ΔH

Given the Following Reactions N₂ (G)+ O₂ (G)→ 2NO (G)ΔH