The frequency of electromagnetic radiation required to promote an electron from n = 2 to n = 4 in a Bohr hydrogen atom is ________ Hz. A)4.13 × 10^-19 B)6.17 × 10¹⁴ C)5.46 × 10^-19 D)8.22 × 10¹⁴ E)4.13 × 10¹⁹

Question

Quizplus · Accepted Answer

The energy required to promote an electron from n=2 to n=4 can be calculated using the equation: 
ΔE = E4 - E2 = (-13.6 eV) [(1/4²) - (1/2²)] - (-13.6 eV) [(1/2²) - (1/1²)]
ΔE = 2.16 eV
Now, we can use the relation between frequency and energy of electromagnetic radiation:
E = hν 
where E is energy, h is Planck's constant, and ν is frequency.
Rearranging, we get:
ν = E/h 
Substituting the values, we get:
ν = (2.16 eV)/(6.626 x 10^-34 J.s) 
ν = 6.17 x 10^14 Hz 
Therefore, the frequency required to promote an electron from n=2 to n=4 is 6.17 x 10^14 Hz, which corresponds to choice B.

The Frequency of Electromagnetic Radiation Required to Promote an Electron