What is the de Broglie wavelength (m)of an electron traveling at a velocity of 6.10 × 10⁶ m/s? A)1.19 × 10^-10 B)8.39 × 10⁹ C)8.39 × 10¹² D)1.19 × 10^-16 E)1.19 × 10^-13

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Quizplus · Accepted Answer

The de Broglie wavelength $\lambda$ of a particle is given by the formula $\lambda = \frac{h}{mv}$, where $h$ is Planck's constant ($6.626 \times 10^{-34} \, \text{m}^2\text{kg/s}$), $m$ is the mass of the particle, and $v$ is its velocity. For an electron with a mass of approximately $9.11 \times 10^{-31}$ kg and given velocity $6.10 \times 10^6$ m/s, substituting these values into the formula yields a wavelength of approximately $1.19 \times 10^{-10}$ meters.

What Is the De Broglie Wavelength (M)of an Electron Traveling