The bond order of any molecule containing equal numbers of bonding and antibonding electrons is ________.
A)0
B)1
C)2
D)3
E)1/2

Question

Quizplus · Accepted Answer

The bond order is calculated by subtracting the number of antibonding electrons from the number of bonding electrons and dividing by 2. If the molecule has equal numbers of bonding and antibonding electrons, then the bond order would be (bonding electrons - bonding electrons)/2 = 0/2 = 0.

The Bond Order of Any Molecule Containing Equal Numbers of Bonding