The volume of a sample of gas (2.49 g)was 752 mL at 1.98 atm and 62 °C.The gas is ________. A)SO₂ B)SO₃ C)NH₃ D)NO₂ E)Ne

Question

Quizplus · Accepted Answer

Using the ideal gas law, PV = nRT, we can calculate the moles of gas present: 
n = PV/RT = (1.98 atm)(0.752 L)/(0.08206 L·atm·K^-1·mol^-1)(335 K) = 0.0351 mol.

The molar mass of the gas can be calculated using the given mass and moles: 
MM = m/n = 2.49 g/0.0351 mol = 70.9 g/mol.

Comparing the calculated molar mass with the molar masses of known gases, we find that it is closest to the molar mass of nitrogen gas (N2), so the gas is most likely nitrogen. Therefore, the correct choice is D) N2.

The Volume of a Sample of Gas (2