A sample of H₂ gas (12.28 g)occupies 100.0 L at 400.0 K and 2.00 atm.A sample weighing 9.49 g occupies ________ L at 353 K and 2.00 atm.

Question

Quizplus · Accepted Answer

The gas sample is kept at constant pressure and amount, so we can use the combined gas law to calculate the new volume:

(P1V1/T1) = (P2V2/T2)

Plugging in the given values, we get:

(2.00 atm x 100.0 L)/(400.0 K) = (2.00 atm x V2)/(353 K)

Solving for V2, we get:

V2 = (2.00 atm x 100.0 L x 353 K) / (2.00 atm x 400.0 K) = 68.2 L

Therefore, the answer is B.

A Sample of H2 Gas (12