A sample of a gas originally at 25 °C and 1.00 atm pressure in a 2.5 L container is subject to a pressure of 0.85 atm and a temperature of 15 °C.The final volume of the gas is ________ L.
A)3.0
B)2.8
C)2.6
D)2.1
E)0.38

Question

Quizplus · Accepted Answer

Using the combined gas law: (P1 * V1) / T1 = (P2 * V2) / T2, where temperatures are in Kelvin. Convert temperatures: 25°C = 298K, 15°C = 288K. Solve for V2: (1.00 atm * 2.5 L) / 298K = (0.85 atm * V2) / 288K. V2 ≈ 2.8 L.

A Sample of a Gas Originally at 25 °C and 1.00