A gas mixture of Xe,Ne,and Ar has a total pressure of 12.20 atm.What is the mole fraction of Xe if the partial pressures of Ne and Ar are 2.10 and 4.50 atm,respectively?
A)0.848
B)0.459
C)5.60
D)2.18
E)1.18

Question

Quizplus · Accepted Answer

The mole fraction of Xe can be calculated using the formula for partial pressures: $P_{total} = P_{Xe} + P_{Ne} + P_{Ar}$. Given $P_{total} = 12.20$ atm, $P_{Ne} = 2.10$ atm, and $P_{Ar} = 4.50$ atm, we can find $P_{Xe} = 12.20 - 2.10 - 4.50 = 5.60$ atm. The mole fraction of Xe is then $P_{Xe} / P_{total} = 5.60 / 12.20 = 0.459$.

A Gas Mixture of Xe,Ne,and Ar Has a Total Pressure