Sulfur dioxide (12.4 g)and carbon dioxide (12.4 g)are placed in a 500.0 mL container at 45.0 °C.What is the partial pressure (atm)of sulfur dioxide in the container?

Question

Quizplus · Accepted Answer

To find the partial pressure of sulfur dioxide, use the ideal gas law: PV = nRT. First, calculate the moles of sulfur dioxide (SO2) using its molar mass (64.07 g/mol): n = 12.4 g / 64.07 g/mol = 0.1935 mol. Then, use the ideal gas law: P = nRT/V. R = 0.0821 L·atm/mol·K, T = 45.0 °C = 318.15 K, V = 0.500 L. P = (0.1935 mol)(0.0821 L·atm/mol·K)(318.15 K) / 0.500 L = 10.1 atm.

Sulfur Dioxide (12