A solution is prepared by dissolving 23.7 g of CaCl₂ in 375 g of water.The density of the resulting solution is .The concentration of Cl^- in this solution is ________ M. A)0.214 B)0.562 C)1.12 D)1.20 E)6.64 × 10^-2

Question

Quizplus · Accepted Answer

First, we need to calculate the amount of CaCl2 dissolved in water:

moles of CaCl2 = 23.7 g / 110.98 g/mol = 0.2134 mol

Next, we need to calculate the total volume of the solution:

V = m / ρ = 375 g / 1.17 g/mL = 320.5 mL = 0.3205 L

Then, we can use the formula for molarity:

Molarity = moles of solute / liters of solution

Molarity of Cl- = 2 x Molarity of CaCl2 = 2 x 0.2134 mol / 0.3205 L = 1.12 M

Therefore, the answer is (C) 1.12.

A Solution Is Prepared by Dissolving 23