At elevated temperatures,methylisonitrile (CH₃NC) isomerizes to acetonitrile (CH₃CN) : CH₃NC (g) → CH₃CN (g)
At the start of the experiment,there are 0.200 mol of reactant (CH₃NC) and 0 mol of product (CH₃CN) in the reaction vessel.After 25 min of reaction,0.108 mol of reactant (CH₃NC) remain. The average rate of decomposition of methyl isonitrile,CH₃NC,in this 25 min period is ________ mol/min.

Question

Quizplus · Accepted Answer

The average rate of decomposition is calculated by dividing the change in concentration of the reactant by the time period. Here, the change in concentration is 0.200 mol - 0.108 mol = 0.092 mol over 25 minutes, so the average rate = 0.092 mol / 25 min = 3.68 × 10^-3 mol/min, which rounds to 3.7 × 10^-3 mol/min.

At Elevated Temperatures,methylisonitrile (CH3NC)isomerizes to Acetonitrile (CH3CN): CH3NC (G)→ CH3CN

At Elevated Temperatures,methylisonitrile (CH₃NC)isomerizes to Acetonitrile (CH₃CN): CH₃NC (G)→ CH₃CN