A second-order reaction has a half-life of 18 s when the initial concentration of reactant is 0.71 M.The rate constant for this reaction is ________ M^-1s^-1.

Question

Quizplus · Accepted Answer

For a second-order reaction, the half-life (t1/2) is given by the formula t1/2 = 1 / (k[A]0), where k is the rate constant and [A]0 is the initial concentration. Rearranging this formula to solve for k gives k = 1 / (t1/2[A]0). Substituting the given values (t1/2 = 18 s, [A]0 = 0.71 M) into this equation yields k = 1 / (18 s * 0.71 M) = 7.8 × 10^-2 M^-1s^-1.

A Second-Order Reaction Has a Half-Life of 18 S When