In the coal-gasification process,carbon monoxide reacts with water to produce carbon dioxide and hydrogen gas.In an experiment,0.35 mol of CO and 0.40 mol of H₂O were placed in a 1.00-L reaction vessel.At equilibrium,there were 0.22 mol of CO remaining.K_eq at the temperature of the experiment is ________.

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Quizplus · Accepted Answer

The reaction is CO + H2O → CO2 + H2. Initially, there are 0.35 mol of CO and 0.40 mol of H2O. At equilibrium, 0.22 mol of CO remains, so 0.35 - 0.22 = 0.13 mol of CO reacted. Since the reaction is 1:1, 0.13 mol of H2O also reacted, and 0.13 mol of CO2 and H2 were produced. At equilibrium, [CO] = 0.22 mol/L, [H2O] = (0.40 - 0.13) mol/L = 0.27 mol/L, [CO2] = 0.13 mol/L, [H2] = 0.13 mol/L. K_eq = ([CO2][H2])/([CO][H2O]) = (0.13*0.13)/(0.22*0.27) ≈ 0.28.

In the Coal-Gasification Process,carbon Monoxide Reacts with Water to Produce