Based on the crystal-field strengths F^-

Question

Based on the crystal-field strengths F^- < CH₂CN < NH₃< NO₂^- < CN^-,which Co (III)complex is most likely high-spin? A)[Co(NH₃)₆]³⁺ B)[Co(NO₂)₆]^3- C)[Co(CN)₆]^3- D)[CoF₆]^3- E)[Co(CH₃CN)₆]³⁺

Quizplus · Accepted Answer

The crystal-field strength order provided indicates that fluoride (F^-) has the weakest field, which means it is least likely to cause pairing of electrons in the d orbitals. Therefore, a complex with fluoride as a ligand, such as [CoF6]3-, is most likely to be high-spin because it will not encourage electron pairing, allowing for more unpaired electrons.

Based on the Crystal-Field Strengths F- < CH2CN < NH3

Based on the Crystal-Field Strengths F^- < CH₂CN < NH₃