A survey of an urban university (population of 25,450) showed that 750 of 1,100 students sampled attended a home football game during the season. Using the 90% level of confidence, what is the confidence interval for the proportion of students attending a football game?
A) [0.7510, 0.8290]
B) [0.6591, 0.7045]
C) [0.6659, 0.6941]
D) [0.6795, 0.6805]

Question

Quizplus · Accepted Answer

The sample proportion is 750/1100 = 0.6818. Using the formula for the confidence interval for a proportion and a 90% confidence level, the interval is approximately [0.6591, 0.7045].

A Survey of an Urban University (Population of 25,450) Showed