specific heat capacity of ice = 2,000 J/kg-°C
latent heat of fusion of water = 334,000 J/kg
specific heat capacity of water = 4,000 J/kg-°C
-A 1 kg block of ice is removed from a freezer where its temperature was -10°C.The amount of heat absorbed by the ice as it warms to 0°C is
A)2,000 J.
B)4,000 J.
C)20,000 J.
D)40,000 J.
E)334,000 J.

Question

Quizplus · Accepted Answer

The amount of heat absorbed by the ice as it warms to 0°C can be calculated using the formula Q = mcΔT, where Q is the amount of heat absorbed, m is the mass of the ice (1 kg), c is the specific heat capacity of ice (2,000 J/kg-°C), and ΔT is the change in temperature (0°C - (-10°C) = 10°C). Thus, Q = (1 kg)(2,000 J/kg-°C)(10°C) = 20,000 J.

Specific Heat Capacity of Ice = 2,000 J/kg-°C