For a body emitting blackbody radiation,the total power emitted is proportional to the 4th power of the body's absolute temperature: (T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: ( in meters,T in kelvins)
Assume an object is emitting blackbody radiation.
-As the temperature of an object increases,the wavelength of the brightest light emitted

Question

For a body emitting blackbody radiation,the total power emitted is proportional to the 4th power of the body's absolute temperature:  (T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:  (  in meters,T in kelvins)
Assume an object is emitting blackbody radiation.
-As the temperature of an object increases,the wavelength of the brightest light emitted

Quizplus · Accepted Answer

According to Wien's Law, as the temperature of an object increases, the wavelength of the peak of its blackbody radiation decreases. This means that the object emits more energy at shorter wavelengths, which corresponds to higher frequency light (bluer colors). Therefore, choice B is correct. The composition and size of the body do not affect the wavelength of the peak of its blackbody radiation.

For a Body Emitting Blackbody Radiation,the Total Power Emitted Is