For a body emitting blackbody radiation,the total power emitted is proportional to the 4th power of the body's absolute temperature: (T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: ( in meters,T in kelvins)
Assume an object is emitting blackbody radiation.
-As the temperature of a body increases,

Question

For a body emitting blackbody radiation,the total power emitted is proportional to the 4th power of the body's absolute temperature:  (T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:  (  in meters,T in kelvins)
Assume an object is emitting blackbody radiation.
-As the temperature of a body increases,

Quizplus · Accepted Answer

As per the given information, the total power emitted by a body emitting blackbody radiation is proportional to the 4th power of the body's absolute temperature. Hence, as the temperature of the body increases, the power emitted by the body also increases, making it brighter. Additionally, the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature, which means as the body's temperature increases, the wavelength of the most intense light decreases. This shift in wavelength also affects the color of the body, making it shift from red to white. Since the frequency of the EM radiation is inversely proportional to the wavelength, the frequency of the most intense light also increases as the temperature of the body increases. Therefore, all the above choices are correct.

For a Body Emitting Blackbody Radiation,the Total Power Emitted Is