The energy level diagram for hydrogen
-The energy of a photon emitted in a transition from the n = 3 state to the n = 2 state is
A)1.5 eV.
B)1.9 eV.
C)3.4 eV.
D)10.2 eV.
E)13.6 eV.

Question

The energy level diagram for hydrogen 
-The energy of a photon emitted in a transition from the n = 3 state to the n = 2 state is
A)1.5 eV. 
B)1.9 eV. 
C)3.4 eV. 
D)10.2 eV. 
E)13.6 eV.

Quizplus · Accepted Answer

The energy of a photon emitted in a transition from n = 3 to n = 2 can be calculated as the difference in energy between these two states. From the energy level diagram, we can see that the energy of the n = 3 state is -1.51 eV and the energy of the n = 2 state is -3.40 eV. So, the energy difference is:

ΔE = E(n=2) - E(n=3) = -3.40 eV - (-1.51 eV) = -1.89 eV

The negative sign indicates that energy is emitted in this transition. Converting this to electron volts gives:

ΔE = (1.89 eV) / (1.60 x 10^-19 J/eV) = 1.18 x 10^-18 J

Therefore, the energy of the photon emitted is 1.89 eV, which is closest to choice B, 1.9 eV.

The Energy Level Diagram for Hydrogen