400.0g of a metal absorbs 10000.J of heat energy and its temperature rises from 20.0^º C to 103.0^º C)What is the specific heat of the metal?

Question

Quizplus · Accepted Answer

The specific heat (c) can be calculated using the formula $q = mc\Delta T$, where $q$ is the heat absorbed (10000 J), $m$ is the mass of the metal (400.0 g), and $\Delta T$ is the change in temperature (103.0 - 20.0 = 83.0°C). Solving for $c$ gives $c = \frac{q}{m\Delta T} = \frac{10000}{400.0 \times 83.0} = 0.301 J/g°C$.

4000g of a Metal Absorbs 10000