The specific heat of aluminum is 0.900J/g^ºC.A 400.0g sample of aluminum at 20.0^ºC absorbs 2520.J of heat energy.What is the new temperature of the aluminum?

Question

Quizplus · Accepted Answer

We can use the formula:
q = m*c*ΔT
where q is the heat absorbed, m is the mass of aluminum, c is the specific heat of aluminum and ΔT is the change in temperature.
Rearranging the formula, we can find ΔT:
ΔT = q/(m*c)
Substituting the given values, we get:
ΔT = 2520 J / (400.0 g * 0.900 J/g°C) = 7°C
Therefore, the new temperature of the aluminum is:
20°C + 7°C = 27°C
Hence, the answer is D.

The Specific Heat of Aluminum Is 0