A 400.0g metal bar requires 6.446 kJ of energy to change its temperature from 18.0^ºC to 95.0^ºC.What is the specific heat of the metal?

Question

Quizplus · Accepted Answer

The specific heat (c) can be calculated using the formula $q = mc\Delta T$, where $q$ is the heat energy (in joules), $m$ is the mass (in grams), $c$ is the specific heat capacity, and $\Delta T$ is the change in temperature (in Celsius). Rearranging the formula to solve for $c$, we get $c = \frac{q}{m\Delta T}$. Plugging in the given values: $c = \frac{6446\, \text{J}}{400\, \text{g} \times (95 - 18)\,^\circ\text{C}} = \frac{6446}{400 \times 77} = \frac{6446}{30800} = 0.209\, \text{J/g}^\circ\text{C}$.

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