How many moles of carbon monoxide are produced when 40.0g of oxygen react completely in the following equation? 2C + O₂ $\rarr$ 2CO

Question

Quizplus · Accepted Answer

First, we need to determine the limiting reagent. To do this, we need to convert the mass of oxygen given to moles using its molar mass:

40.0g O2 x (1 mol O2 / 32.00 g O2) = 1.25 mol O2

Now we compare the moles of oxygen to the mole ratio of oxygen to carbon in the balanced chemical equation (2:1). Since we have more oxygen than necessary, it is the excess reagent and carbon is the limiting reagent.

Using the mole ratio between carbon monoxide and carbon in the balanced equation (2:2), we can determine the moles of CO produced:

1.25 mol O2 x (2 mol CO/2 mol C) = 1.25 mol CO

Thus, the answer is choice C, 2.50 mol CO (since there are 2 moles of CO produced for every 2 moles of C, which equals 1.25 x 2 = 2.50 mol CO produced).

How Many Moles of Carbon Monoxide Are Produced When 40 →\rarr→

How Many Moles of Carbon Monoxide Are Produced When 40 $\rarr$