A sample of gas has a volume of 200.mL at 20.0^°C.What will be its volume at 40.0^°C, pressure remaining constant?

Question

Quizplus · Accepted Answer

To solve this problem, we can use the combined gas law:

(P1V1)/T1 = (P2V2)/T2

where P is pressure, V is volume, and T is temperature in Kelvin. Note that we need to convert the temperatures to Kelvin by adding 273.15.

Plugging in the given values:

(P1) = (P2)  (pressure remains constant)
V1 = 200. mL
T1 = 20.0°C + 273.15 = 293.15 K
T2 = 40.0°C + 273.15 = 313.15 K
V2 = ?

(P1V1)/T1 = (P2V2)/T2

V2 = (P1V1 * T2) / (T1 * P2)
V2 = (1 atm * 200. mL * 313.15 K) / (293.15 K * 1 atm)
V2 ≈ 214 mL

Therefore, the best choice is (B) 214 mL.

A Sample of Gas Has a Volume of 200