A sample of gas has a volume of 850.mL at 23.0^°C and 1.10 atm.The temperature is increased to 33.0^°C,at what pressure will its volume be 900.mL?

Question

Quizplus · Accepted Answer

To find the new pressure, we can use the combined gas law, which is $P_1V_1/T_1 = P_2V_2/T_2$, where $P$ is pressure, $V$ is volume, and $T$ is temperature in Kelvin. First, convert temperatures to Kelvin: $T_1 = 23.0 + 273.15 = 296.15 K$ and $T_2 = 33.0 + 273.15 = 306.15 K$. Then, solve for $P_2$: $P_2 = P_1V_1T_2 / (T_1V_2) = (1.10 atm)(850 mL)(306.15 K) / (296.15 K)(900 mL) ≈ 1.07 atm$.

A Sample of Gas Has a Volume of 850