What is the volume of 1.40 moles of nitrogen gas at 20.0^°C and 770.torr?

Question

Quizplus · Accepted Answer

To find the volume of a gas, we can use the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. First, we need to convert the given conditions to the appropriate units: 770 torr to atm (since 1 atm = 760 torr, 770 torr = 770/760 atm), and 20°C to Kelvin (20 + 273.15 = 293.15 K). Using R = 0.0821 L·atm/(mol·K), we can solve for V. V = nRT/P = (1.40 moles)(0.0821 L·atm/(mol·K))(293.15 K) / (770/760 atm) ≈ 33.2 L.

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