What is the freezing point of a 1.0 m aqueous solution of CaCl₂? (The freezing point depression constant for water is 1.86^°C/m. )

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Quizplus · Accepted Answer

CaCl2 dissociates into 3 ions (Ca^2+ and 2 Cl^-), so the van't Hoff factor (i) is 3. The freezing point depression is calculated as ΔTf = i * Kf * m = 3 * 1.86°C/m * 1.0 m = 5.58°C. The freezing point of the solution is 0°C - 5.58°C = -5.58°C.

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