In an artificial transmutation process,a nucleus of Al-27 is absorbs an alpha particle and emits a neutron.What is the new nuclide formed?

Question

Quizplus · Accepted Answer

In an artificial transmutation process, when an Al-27 nucleus absorbs an alpha particle (which has a mass number of 4 and an atomic number of 2) and emits a neutron (which has a mass number of 1 and no charge), the new nuclide formed will have a mass number increased by 3 (27 + 4 - 1 = 30) and an atomic number increased by 2 (13 + 2 - 0 = 15, where 13 is the atomic number of Al). The element with atomic number 15 is Phosphorus (P), making the new nuclide P-30.

In an Artificial Transmutation Process,a Nucleus of Al-27 Is Absorbs