The half-life of Sn-110 is 4 hours.If you have 20.g of this isotope,how much would remain 8 hours later?

Question

Quizplus · Accepted Answer

Since the half-life of Sn-110 is 4 hours, we can use the half-life equation:

N = N₀(1/2)^(t/T)

where:
N₀ = initial amount of Sn-110 (20.g)
N = remaining amount after 8 hours
t = time elapsed (8 hours)
T = half-life (4 hours)

Substituting the values, we get:

N = 20.g(1/2)^(8/4)
N = 20.g(1/2)^2
N = 20.g(1/4)
N = 5.g

Therefore, only 5.g of Sn-110 would remain after 8 hours. The best choice is B.

The Half-Life of Sn-110 Is 4 Hours