How many grams of N₂ are required to completely react with 3.03 grams of H₂ for the following balanced chemical equation? N₂ + 3H₂ $\rarr$ 2NH₃

Question

Quizplus · Accepted Answer

From the balanced chemical equation, we can see that 1 mol of N₂ reacts with 3 mol of H₂ to form 2 mol of NH₃. First, we need to convert the given mass of H₂ to moles: 3.03 g H₂ / (32.06 g/mol) = 0.0945 mol H₂ Using the mole ratio from the balanced chemical equation, we can determine the moles of N₂ required: 1 mol N₂ / 3 mol H₂ = x mol N₂ / 0.0945 mol H₂ x = 0.3149 mol N₂ Finally, we can convert the moles of N₂ to grams: 0.3149 mol N₂ x 92.06 g/mol = 28.99 g N₂ Rounded to two significant figures, this gives us 29.0 g N₂. Therefore, the best choice is C.

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