Given the following: heat of fusion of ice = 80.0 cal/g;specific heat of ice = 0.480 cal/g;and specific heat of water = 1.00 cal/g.Calculate the amount of heat required to melt 30.0 g of ice at 0 $\circ$ C.

Question

Quizplus · Accepted Answer

The heat required to melt ice is calculated using the heat of fusion. For 30.0 g of ice, the heat required is 30.0 g * 80.0 cal/g = 2400 cal, which is equivalent to 2.40 kcal.

Given the Following: Heat of Fusion of Ice = 80 ∘\circ∘

Given the Following: Heat of Fusion of Ice = 80 $\circ$