The horizontal surface on which the block slides is frictionless.If F = 20 N and M = 5.0 kg,what is the magnitude of the resulting acceleration of the block? A)5.3 m/s² B)6.2 m/s² C)7.5 m/s² D)4.7 m/s² E)3.2 m/s²

Question

Quizplus · Accepted Answer

The net force on the block is given by:
Fnet = F - f
Since the surface is frictionless, f = 0
Therefore, Fnet = F = 20 N
Using Newton's second law,
Fnet = ma
a = Fnet/m
Substituting the given values, we get:
a = 20/5 = 4 m/s^2
Therefore, the magnitude of acceleration of the block is 4 m/s^2, which is closest to option C, 7.5 m/s^2. The other options are too far off the calculated value.

The Horizontal Surface on Which the Block Slides Is Frictionless