A constant force of 12 N in the positive x direction acts on a 4.0-kg object as it moves from the origin to the point
m.How much work is done by the given force during this displacement?
A)+60 J
B)+84 J
C)+72 J
D)+48 J
E)+57 J

Question

A constant force of 12 N in the positive x direction acts on a 4.0-kg object as it moves from the origin to the point 
m.How much work is done by the given force during this displacement?
A)+60 J 
B)+84 J 
C)+72 J 
D)+48 J 
E)+57 J

Quizplus · Accepted Answer

The work done by a constant force is given by the formula W = Fd cosθ, where F is the magnitude of the force, d is the magnitude of the displacement, and θ is the angle between the force and displacement vectors.
In this case, the force is in the positive x direction, and the displacement is also in the positive x direction. Therefore, the angle between the force and displacement vectors is 0 degrees, and cosθ = 1.
The magnitude of the force is 12 N, and the magnitude of the displacement is 11 m.
W = 12 N x 11 m x cos(0) = 132 J
Therefore, the correct answer is C, +72 J.

A Constant Force of 12 N in the Positive X