A car of mass 1 000 kg moves with a speed of 50 m/s on a circular track of radius 100 m. What is the magnitude of its angular momentum (in kg⋅m²/s) relative to the center of the race track? A) 5.0 × 10² B) 5.0 × 10⁶ C) 2.5 × 10⁴ D) 2.5 × 10⁶ E) 5.0 × 10³

Question

Quizplus · Accepted Answer

Angular momentum is given by L = Iω, where I is the moment of inertia and ω is the angular velocity. For a point mass, I = mr^2, where m is the mass and r is the distance from the axis of rotation. In this case, m = 1000 kg, r = 100 m, and ω = v/r = 50 m/s / 100 m = 0.5 rad/s. Therefore, L = (1000 kg)(100 m)^2(0.5 rad/s) = 5.0 × 10^6 kg⋅m^2/s.

A Car of Mass 1 000 Kg Moves with a Speed