At sea level,at a latitude where
,a pendulum that takes 2.00 s for a complete swing back and forth has a length of 0.993 m.What is the value of g in m/s² at a location where the length of such a pendulum is 0.970 m?

Question

At sea level,at a latitude where

,a pendulum that takes 2.00 s for a complete swing back and forth has a length of 0.993 m.What is the value of g in m/s² at a location where the length of such a pendulum is 0.970 m?

Quizplus · Accepted Answer

We can use the equation for the period of a simple pendulum:

T = 2π√(L/g)

where T is the period, L is the length of the pendulum and g is the acceleration due to gravity.

At the first location, we have:

T1 = 2.00 s 
L1 = 0.993 m

Solving for g1:

g1 = (4π^2 * L1) / T1^2 = 9.81 m/s^2

At the second location, we have:

T2 = 2.00 s 
L2 = 0.970 m

Solving for g2:

g2 = (4π^2 * L2) / T2^2 = 9.57 m/s^2

Therefore, the answer is C) 9.57 m/s^2.

At Sea Level,at a Latitude Where