If y = 0.02 sin (30x − 400t) (SI units), the wavelength of the wave is
A) π/15 m
B) 15/π m
C) 60π m
D) 4.2 m
E) 30 m

Question

Quizplus · Accepted Answer

The wavelength $\lambda$ can be found from the wave equation $y = A \sin(kx - \omega t)$, where $k = \frac{2\pi}{\lambda}$. In the given equation, $30x - 400t$, comparing it to $kx - \omega t$, we find $k = 30$. Solving $30 = \frac{2\pi}{\lambda}$ for $\lambda$ gives $\lambda = \frac{2\pi}{30} = \frac{\pi}{15}$ meters.

If Y = 002 Sin (30x − 400t) (SI Units), the Wavelength of the Wavelength