A parallel plate capacitor of capacitance C₀ has plates of area A with separation d between them.When it is connected to a battery of voltage V₀,it has charge of magnitude Q₀ on its plates.It is then disconnected from the battery and the space between the plates is filled with a material of dielectric constant 3.After the dielectric is added,the magnitudes of the charge on the plates and the potential difference between them are A) Q₀, V₀. B)Q₀, V₀. C)Q₀,V₀. D)Q₀,3V₀. E)3Q₀,3V₀.

Question

Quizplus · Accepted Answer

When the dielectric is added, the capacitance of the capacitor increases by a factor of the dielectric constant (C'=kC). Therefore, the new capacitance is 3CS. Since the charge on the plates cannot change, the potential difference between the plates must decrease by a factor of 3 (V'=V/3). Therefore, the magnitudes of the charge on the plates and the potential difference between them are Q₀ and 11ea7ff9_2bea_e53d_a768_4dce00ca7f00_TB2295_11 V₀, respectively. Therefore, the correct answer is B.

A Parallel Plate Capacitor of Capacitance C0 Has Plates of Area

A Parallel Plate Capacitor of Capacitance C₀ Has Plates of Area