What is the potential difference V_B − V_A when the I = 1.5 A in the circuit segment below? A)+22 V B)−22 V C)−38 V D)+38 V E)+2.0 V

Question

Quizplus · Accepted Answer

Using Kirchhoff's voltage law on the outer loop, we can write: V_B − V_A − 8V − 6I = 0 Plugging in the given value of I, we get: V_B − V_A − 8V − 9 = 0 Simplifying, we get: V_B − V_A = 9 + 8V Now, we know that point B1 is connected to both the 12V source and the 4Ω resistor. Therefore, we can use the voltage divider rule to find the potential difference across the 4Ω resistor: V4Ω = (4Ω/(4Ω+2Ω)) × 12V = 8V Now, using Kirchhoff's voltage law on the inner loop, we can write: −V4Ω − 6I + V_A = 0 Plugging in the given value of I and the value of V4Ω, we get: −8 − 9 + V_A = 0 Simplifying, we get: V_A = 17V Finally, we can calculate the potential difference by subtracting V_A from V_B: V_B − V_A = (9 + 8V) - 17V = -22V Therefore, the answer is B: −22V.

What Is the Potential Difference VB − VA When the I

What Is the Potential Difference V_B − V_A When the I