An ideal solenoid of radius a has n turns per unit length and current I.The magnetic flux Φ_B through any area completely inside the solenoid,centered on the solenoid axis but at a 45° angle to the axis,so that it touches the inside of the solenoid,as shown below,is A) . B) . C)μ₀πa²nI. D)2μ₀πa²nI. E)0.

Question

Quizplus · Accepted Answer

The magnetic field inside the solenoid is given by BS1U1B0=μnI. And, for a Gaussian surface lying completely inside the solenoid, the magnetic flux through that surface is given by ΦS1U1B1BS1U1B0=B0πa2cos(45°). Therefore, substituting the values, we get ΦS1U1B1BS1U1B0=μnIπa2cos(45°). Simplifying this expression gives us ΦS1U1B1BS1U1B0=μS1U1B10S1U1B0πaS1U1P12S1S1P0nI, which is equivalent to option C.

An Ideal Solenoid of Radius a Has N Turns Per