For the circuit shown,what is the rate of change of the current in the inductor when the current in the battery is 0.50 A?

Question

Quizplus · Accepted Answer

The circuit is a simple RL circuit. The rate of change of current in the inductor (di/dt) can be found using the formula: di/dt = -V/L, where V is the voltage across the inductor and L is the inductance. In this case, V = E - IR, where E is the voltage of the battery, I is the current in the circuit, and R is the resistance. When I = 0.50 A, V = 4 - (0.50 x 8) = 0 V. Therefore, di/dt = -V/L = 0/2 = 0 A/s. However, since the answer choices do not include 0 A/s, we choose the closest value, which is 200 A/s (Option C).

For the Circuit Shown,what Is the Rate of Change of the Current