Approximately how much uranium (in kg)must undergo fission per day to provide 1 000 MW of power? (Assume an efficiency of 30%).The nuclear reaction is ) m(n.= 1.008 665 u m(U.= 235.043 915 u M(Ba)= 140.913 9 u M(Kr)= 91.897 3 u U = 1.66 × 10−²⁷ kg A)1.0 B)3.5 C)2.3 D)4.6 E)0.1

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The Answer of Approximately how much uranium (in kg)must undergo fission per day to provide 1 000 MW of power? (Assume an efficiency of 30%).The nuclear reaction is ) m(n.= 1.008 665 u m(U.= 235.043 915 u M(Ba)= 140.913 9 u M(Kr)= 91.897 3 u U = 1.66 × 10−²⁷ kg A)1.0 B)3.5 C)2.3 D)4.6 E)0.1

Approximately How Much Uranium (In Kg)must Undergo Fission Per Day