What would be the temperature of 50 g of 20°C water mixed with 80 g of 40°C water?

Question

Quizplus · Accepted Answer

Explanation:Heat lost by hot water = m1 * c * (T1 - T)= 80 * 4.18 * (40 - T)= 1356.8 - 334.4THeat gained by cold water = m2 * c * (T - T2)= 50 * 4.18 * (T - 20)= 209 - 83.6TEquating heat lost and heat gained, we get:1356.8 - 334.4T = 209 - 83.6T251.8T = 1147.8T = 4.56°CTherefore, the temperature of the mixture will be 20 + 4.56 = 24.56°C, which is closest to option A) 24.6°C.

What Would Be the Temperature of 50 G of 20°C