One mole of ammonia (NH₃)has a mass of 17.0 g,and one mole is equal to 6.02 × 10²³ molecules.How many hydrogen (H)atoms are in 55.0 g of ammonia? Note that each molecule of ammonia has 3 hydrogen atoms. A)5.84E+24 B)1.95E+24 C)3.07E+25 D)6.49E+23

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Quizplus · Accepted Answer

55.0 g of ammonia is equivalent to $55.0 \, \text{g} \div 17.0 \, \text{g/mol} = 3.235 \, \text{mol}$. Since one mole of ammonia contains $6.02 \times 10^{23}$ molecules, and each molecule has 3 hydrogen atoms, the total number of hydrogen atoms in 55.0 g of ammonia is $3.235 \, \text{mol} \times 6.02 \times 10^{23} \, \text{molecules/mol} \times 3 = 5.84 \times 10^{24}$ hydrogen atoms.

One Mole of Ammonia (NH3)has a Mass of 17

One Mole of Ammonia (NH₃)has a Mass of 17