A 50.0-g ball traveling at 22.0 m/s is bounced off a brick wall and rebounds at 21.0 m/s.A high-speed camera records this event.If the ball is in contact with the wall for 2.50 ms,what is the average acceleration of the ball during this time interval?

Question

Quizplus · Accepted Answer

The average acceleration can be calculated using the formula: a = (v_f - v_i) / Δt. Here, v_i = 22.0 m/s, v_f = -21.0 m/s (since it rebounds in the opposite direction), and Δt = 2.50 ms = 0.0025 s. Thus, a = (-21.0 - 22.0) / 0.0025 = -43.0 / 0.0025 = -1.72E+4 m/s².

A 500-G Ball Traveling at 22