When a drag strip vehicle reaches a velocity of 65.0 m/s,it begins a negative acceleration by releasing a drag chute and applying its brakes.While reducing its velocity back to zero,its acceleration along a straight-line path is a constant −7.10 m/s².What displacement does it undergo during this deceleration period? A)595 m B)4.58 m C)2 110 m D)298 m E)9.15 m

Question

Quizplus · Accepted Answer

We can use the kinematic equation:
v^2 = u^2 + 2as
where,
v = final velocity = 0 m/s
u = initial velocity = 65.0 m/s
a = acceleration = -7.10 m/s^2
s = displacement

Rearranging the equation, we get:
s = (v^2 - u^2) / 2a

Substituting the values, we get:
s = (0 - (65.0)^2) / (2 x (-7.10))
s = 298 m

Therefore, the displacement undergone by the vehicle during the deceleration period is 298 m. The option (D) is the correct answer.

When a Drag Strip Vehicle Reaches a Velocity of 65