John throws a baseball from the outfield from shoulder height,at an initial velocity of 41.5 m/s at an initial angle of 40.0° with respect to the horizontal.The ball is in its trajectory for a total interval of 5.00 s before the third baseman catches it at an equal shoulder-height level.(Assume air resistance negligible. )What is the ball's horizontal displacement?
A)159 m
B)267 m
C)174 m
D)zero
E)495 m

Question

John throws a baseball from the outfield from shoulder height,at an initial velocity of 41.5 m/s at an initial angle of 40.0° with respect to the horizontal.The ball is in its trajectory for a total interval of 5.00 s before the third baseman catches it at an equal shoulder-height level.(Assume air resistance negligible. )What is the ball's horizontal displacement?​
A)159 m
B)267 m
C)174 m
D)zero
E)495 ​m

Quizplus · Accepted Answer

The horizontal displacement can be calculated using the formula $d = v \cos(\theta) t$, where $v$ is the initial velocity, $\theta$ is the angle of projection, and $t$ is the time of flight. Given $v = 41.5 \, \text{m/s}$, $\theta = 40^\circ$, and $t = 5.0 \, \text{s}$, the displacement is $d = 41.5 \cos(40^\circ) \times 5.0 \approx 159 \, \text{m}$.

John Throws a Baseball from the Outfield from Shoulder Height,at