A ball is rolled horizontally off a table with an initial speed of 0.24 m/s.A stopwatch measures the ball's trajectory time from table to the floor to be 0.36 s.What is the height of the table? (g = 9.8 m/s² and air resistance is negligible) A)0.72 m B)0.55 m C)0.016 m D)0.64 m E)0.65 m

Question

Quizplus · Accepted Answer

Using kinematic equations:
d = v_i*t + (1/2)*a*t^2
Here, initial velocity v_i = 0 (horizontally)
time t = 0.36 s
acceleration a = g = 9.8 m/s^2 (vertically downwards)
We need to find distance d, which is the height of the table.
Using the above equation for vertical motion:
d = (1/2)*g*t^2
Substitute the given values, we get:
d = (1/2)*9.8*(0.36)^2 = 0.64 m (rounded off to two decimal places)

A Ball Is Rolled Horizontally Off a Table with an Initial