A projectile is thrown horizontally at 11.5 m/s.The projectile hits the ground 0.570 s later.What is the angle of impact the projectile makes with the horizontal ground?
A)-29.1°
B)-25.9°
C)119°
D)-89.7°
E)-64.1°

Question

Quizplus · Accepted Answer

First, we need to determine the distance the projectile traveled horizontally:

d = v*t
d = 11.5 m/s * 0.570 s
d = 6.55 m

Now, we need to determine the vertical distance the projectile fell during this time. We can use the formula:

d = (1/2)*a*t^2

Since the projectile is only traveling horizontally, the initial vertical velocity is 0 m/s. Thus,

d = (1/2)*g*t^2
d = (1/2)*9.81 m/s^2 * (0.570 s)^2
d = 1.68 m

Now we can find the angle using trigonometry. The tangent of the angle is the opposite (1.68 m) divided by the adjacent (6.55 m):

tan(angle) = 1.68 m / 6.55 m
angle = arctan(1.68 m / 6.55 m)
angle = 25.9°

Therefore, the answer is B.

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