A horizontal force of 675 N is needed to overcome the force of static friction between a level floor and a 300-kg crate.What is the acceleration of the crate if the 675-N force is maintained after the crate begins to move and the coefficient of kinetic friction is 0.15? A)0.78 m/s² B)3.7 m/s² C)3.3 m/s² D)1.5 m/s² E)1.8 m/s²

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Quizplus · Accepted Answer

The force of kinetic friction is 0.15 * 300 * 9.8 = 441 N. The net force on the crate is 675 - 441 = 234 N. The acceleration of the crate is 234 / 300 = 0.78 m/s^2.

A Horizontal Force of 675 N Is Needed to Overcome