A 16.0-kg mass and a 2.25-kg mass are connected by a light string over a massless,frictionless pulley.If g = 9.8 m/s²,what is the acceleration of the system when released? A)13.0 m/s² B)7.38 m/s² C)179 m/s² D)9.80 m/s² E)1.86 m/s²

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Quizplus · Accepted Answer

The acceleration of the system can be calculated using the formula $a = \frac{(m_1 - m_2)g}{m_1 + m_2}$, where $m_1$ is the mass of the heavier object, $m_2$ is the mass of the lighter object, and $g$ is the acceleration due to gravity. Substituting the given values, $a = \frac{(16.0\,kg - 2.25\,kg) \times 9.8\,m/s^2}{16.0\,kg + 2.25\,kg} = 7.38\,m/s^2$.

A 160-Kg Mass and a 2